BloombergLP::bdldfp::operator/

Divide the specified lhs by the value of the specified rhs as described by IEEE-754, and return the result.

Synopsis

Declared in <bdldfp_decimal.h>

bdldfp::Decimal64
operator/(
    int lhs,
    Decimal64 rhs);

Description

* If rhs is signaling NaN, then store the value of the macro EDOM into errno and return a NaN. * Otherwise if rhs is NaN then return a NaN. * Otherwise if rhs is infinity (positive or negative), and lhs is zero, store the value of the macro ERANGE into errno and return a NaN. * Otherwise if rhs is zero (positive or negative), store the value of the macro ERANGE into errno and return infinity with the sign of lhs. * Otherwise if dividing the value of lhs by the value of rhs results in an absolute value that is larger than std::numeric_limits<Decimal64>::max() then store the value of the macro ERANGE into errno and return infinity with the same sign as that result. * Otherwise if dividing the value of lhs by the value of rhs results in an absolute value that is smaller than std::numeric_limits<Decimal64>::min() then store the value of the macro ERANGE into errno and return zero with the same sign as that result. * Otherwise return the result of dividing the value of lhs by the value of rhs. Note that this is a floating-point operation, not integer.