[#BloombergLP-bdldfp-operator_minus-02a]
= xref:BloombergLP.adoc[BloombergLP]::xref:BloombergLP/bdldfp.adoc[bdldfp]::operator‐
:relfileprefix: ../../
:mrdocs:

Subtract the value of the specified `rhs` from the value of the specified `lhs` as described by IEEE‐754 and return the result.

== Synopsis

Declared in `<bdldfp_decimal.h>`

[source,cpp,subs="verbatim,replacements,macros,-callouts"]
----
xref:BloombergLP/bdldfp/Decimal32.adoc[bdldfp::Decimal32]
operator‐(
    xref:BloombergLP/bdldfp/Decimal32.adoc[Decimal32] lhs,
    xref:BloombergLP/bdldfp/Decimal32.adoc[Decimal32] rhs);
----

== Description

* If either of `lhs` or `rhs` is signaling NaN, then store the value of the macro `EDOM` into `errno` and return a NaN. * Otherwise if either of `lhs` or `rhs` is NaN, return a NaN. * Otherwise if `lhs` and the `rhs` have infinity values of the same sign, store the value of the macro `EDOM` into `errno` and return a NaN. * Otherwise if `lhs` and the `rhs` have infinity values of differing signs, then return `lhs`. * Otherwise if the subtracting of `lhs` and `rhs` has an absolute value that is larger than `std::numeric_limits<Decimal32>::max()` then store the value of the macro `ERANGE` into `errno` and return infinity with the same sign as that result. * Otherwise return the result of subtracting the value of `rhs` from the value of `lhs`.


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