This class template defines functors that can search for the sequence of value_type values defined on construction (i.e., the "needle") in sequences of value_type values (i.e., "haystacks") passed to the functor's operator().

Synopsis

Declared in <bslstl_defaultsearcher.h>

template<
    class FORWARD_ITR_NEEDLE,
    class EQUAL = bsl::equal_to<bsl::iterator_traits<FORWARD_ITR_NEEDLE>::value_type>>
class DefaultSearcher;

Member Functions

Name

Description

DefaultSearcher [constructor]

Create a DefaultSearcher object that can search for the sequence of value_type values found in the specified range [needleFirst, needleLast)]. Optionally supply an equal functor for use by operator(). The behavior is undefined unless needleFirst can be advanced to equal needleLast.

equal

Return the functor used by this searcher object to compare value_type values.

needleFirst

Return an iterator referring to the first element of the sequence of value_type values that can be sought by this searcher object.

needleLast

Return an iterator referring to one past the last element of the sequence of value_type values that can be sought by this searcher object.

operator()

Search the specified range [haystackFirst, haystackLast)] for the first sequence of value_type values specified on construction. Return the range where those values are found, or the range [haystackLast, haystackLast)] if that sequence is not found. The search is performed using a "naive" algorithm that has time complexity of: ` bsl::distance(needleFirst(), needleLast()) * bsl::distance(haystackFirst, haystackLast); ` Values of the "needle" sequence and the "haystack" sequence are compared using the equality comparison functor specified on construction. The behavior is undefined unless haystackFirst can be advanced to equal haystackLast and the iterators used to construct this object, needleFirst() and needleLast(), are still valid. Note that if the "needle" sequence is empty, the range [haystackFirst, haystackFirst)] is returned. Also note that if the "needle" sequence is longer than the "haystack" sequence ‐‐ thus, impossible for the "needle" to be found in the "haystack" ‐‐ the range [haystackLast, haystackLast)] is returned.

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