absl::operator>=

Compares a span and a container lexicographically.

Synopsis

Declared in <absl/types/span.h>

template<
    typename T,
    typename U,
    typename = span_internal::EnableIfConvertibleTo<U, absl::Span<T const>>>
constexpr
bool
operator>=(
    Span<T> a,
    U const& b);

Return Value

true if a is not lexicographically less than b.

Parameters

NameDescription
aThe left operand.
bThe right operand.